common.or
common.or
Let's consider two consecutive even numbers as 2n and 2n+2, where n is any integer.
The square of 2n is (2n)^2 = 4n^2. The square of 2n+2 is (2n+2)^2 = 4(n+1)^2.
Now, let's find the difference between these squares:
X = (2n+2)^2 - (2n)^2 X = 4(n+1)^2 - 4n^2
Now, factor out 4:
X = 4[(n+1)^2 - n^2]
Now, simplify the expression inside the square brackets:
X = 4[(n^2 + 2n + 1) - n^2]
X = 4(2n + 1)
X = 8n + 4
Now, we can see that X is divisible by 4 because it has a factor of 4. So, the correct answer is 4.
